关于一种以“bill”开头的变异MD5加密方式的破解方法

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关于一种以“bill”开头的变异MD5加密方式的破解方法,Asp 变异 MD5 加密模块。

偶然间看到个求解密帖子,大概研究了下,做一下记录,以后可能用得着。


原帖标题为:求教一个md5加密算法怎么解密!

内容为:

 31 Then
        Err.Raise 6
    End If

    If (lValue And m_l2Power(31 - iShiftBits)) Then
        LShift = ((lValue And m_lOnBits(31 - (iShiftBits + 1))) * m_l2Power(iShiftBits)) Or &H80000000
    Else
        LShift = ((lValue And m_lOnBits(31 - iShiftBits)) * m_l2Power(iShiftBits))
    End If
End Function

Private Function RShift(lValue, iShiftBits)
    If iShiftBits = 0 Then
        RShift = lValue
        Exit Function
    ElseIf iShiftBits = 31 Then
        If lValue And &H80000000 Then
            RShift = 1
        Else
            RShift = 0
        End If
        Exit Function
    ElseIf iShiftBits  31 Then
        Err.Raise 6
    End If
    
    RShift = (lValue And &H7FFFFFFE)  m_l2Power(iShiftBits)

    If (lValue And &H80000000) Then
        RShift = (RShift Or (&H40000000  m_l2Power(iShiftBits - 1)))
    End If
End Function

Private Function RotateLeft(lValue, iShiftBits)
    RotateLeft = LShift(lValue, iShiftBits) Or RShift(lValue, (32 - iShiftBits))
End Function

Private Function AddUnsigned(lX, lY)
    Dim lX4
    Dim lY4
    Dim lX8
    Dim lY8
    Dim lResult

    lX8 = lX And &H80000000
    lY8 = lY And &H80000000
    lX4 = lX And &H40000000
    lY4 = lY And &H40000000

    lResult = (lX And &H3FFFFFFF) + (lY And &H3FFFFFFF)

    If lX4 And lY4 Then
        lResult = lResult Xor &H80000000 Xor lX8 Xor lY8
    ElseIf lX4 Or lY4 Then
        If lResult And &H40000000 Then
            lResult = lResult Xor &HC0000000 Xor lX8 Xor lY8
        Else
            lResult = lResult Xor &H40000000 Xor lX8 Xor lY8
        End If
    Else
        lResult = lResult Xor lX8 Xor lY8
    End If

    AddUnsigned = lResult
End Function

Private Function md5_F(x, y, z)
    md5_F = (x And y) Or ((Not x) And z)
End Function

Private Function md5_G(x, y, z)
    md5_G = (x And z) Or (y And (Not z))
End Function

Private Function md5_H(x, y, z)
    md5_H = (x Xor y Xor z)
End Function

Private Function md5_I(x, y, z)
    md5_I = (y Xor (x Or (Not z)))
End Function

Private Sub md5_FF(a, b, c, d, x, s, ac)
    a = AddUnsigned(a, AddUnsigned(AddUnsigned(md5_F(b, c, d), x), ac))
    a = RotateLeft(a, s)
    a = AddUnsigned(a, b)
End Sub

Private Sub md5_GG(a, b, c, d, x, s, ac)
    a = AddUnsigned(a, AddUnsigned(AddUnsigned(md5_G(b, c, d), x), ac))
    a = RotateLeft(a, s)
    a = AddUnsigned(a, b)
End Sub

Private Sub md5_HH(a, b, c, d, x, s, ac)
    a = AddUnsigned(a, AddUnsigned(AddUnsigned(md5_H(b, c, d), x), ac))
    a = RotateLeft(a, s)
    a = AddUnsigned(a, b)
End Sub

Private Sub md5_II(a, b, c, d, x, s, ac)
    a = AddUnsigned(a, AddUnsigned(AddUnsigned(md5_I(b, c, d), x), ac))
    a = RotateLeft(a, s)
    a = AddUnsigned(a, b)
End Sub

Private Function ConvertToWordArray(sMessage)
    Dim lMessageLength
    Dim lNumberOfWords
    Dim lWordArray()
    Dim lBytePosition
    Dim lByteCount
    Dim lWordCount
    
    Const MODULUS_BITS = 512
    Const CONGRUENT_BITS = 448
    
    lMessageLength = Len(sMessage)
    
    lNumberOfWords = (((lMessageLength + ((MODULUS_BITS - CONGRUENT_BITS)  BITS_TO_A_BYTE))  (MODULUS_BITS  BITS_TO_A_BYTE)) + 1) * (MODULUS_BITS  BITS_TO_A_WORD)
    ReDim lWordArray(lNumberOfWords - 1)
    
    lBytePosition = 0
    lByteCount = 0
    Do Until lByteCount >= lMessageLength
        lWordCount = lByteCount  BYTES_TO_A_WORD
        lBytePosition = (lByteCount Mod BYTES_TO_A_WORD) * BITS_TO_A_BYTE
        lWordArray(lWordCount) = lWordArray(lWordCount) Or LShift(Asc(Mid(sMessage, lByteCount + 1, 1)), lBytePosition)
        lByteCount = lByteCount + 1
    Loop

    lWordCount = lByteCount  BYTES_TO_A_WORD
    lBytePosition = (lByteCount Mod BYTES_TO_A_WORD) * BITS_TO_A_BYTE

    lWordArray(lWordCount) = lWordArray(lWordCount) Or LShift(&H80, lBytePosition)

    lWordArray(lNumberOfWords - 2) = LShift(lMessageLength, 3)
    lWordArray(lNumberOfWords - 1) = RShift(lMessageLength, 29)
    
    ConvertToWordArray = lWordArray
End Function

Private Function WordToHex(lValue)
    Dim lByte
    Dim lCount
    
    For lCount = 0 To 3
        lByte = RShift(lValue, lCount * BITS_TO_A_BYTE) And m_lOnBits(BITS_TO_A_BYTE - 1)
        WordToHex = WordToHex & Right("0" & Hex(lByte), 2)
    Next
End Function

Public Function MD5(sMessage)
    m_lOnBits(0) = CLng(1)
    m_lOnBits(1) = CLng(3)
    m_lOnBits(2) = CLng(7)
    m_lOnBits(3) = CLng(15)
    m_lOnBits(4) = CLng(31)
    m_lOnBits(5) = CLng(63)
    m_lOnBits(6) = CLng(127)
    m_lOnBits(7) = CLng(255)
    m_lOnBits(8) = CLng(511)
    m_lOnBits(9) = CLng(1023)
    m_lOnBits(10) = CLng(2047)
    m_lOnBits(11) = CLng(4095)
    m_lOnBits(12) = CLng(8191)
    m_lOnBits(13) = CLng(16383)
    m_lOnBits(14) = CLng(32767)
    m_lOnBits(15) = CLng(65535)
    m_lOnBits(16) = CLng(131071)
    m_lOnBits(17) = CLng(262143)
    m_lOnBits(18) = CLng(524287)
    m_lOnBits(19) = CLng(1048575)
    m_lOnBits(20) = CLng(2097151)
    m_lOnBits(21) = CLng(4194303)
    m_lOnBits(22) = CLng(8388607)
    m_lOnBits(23) = CLng(16777215)
    m_lOnBits(24) = CLng(33554431)
    m_lOnBits(25) = CLng(67108863)
    m_lOnBits(26) = CLng(134217727)
    m_lOnBits(27) = CLng(268435455)
    m_lOnBits(28) = CLng(536870911)
    m_lOnBits(29) = CLng(1073741823)
    m_lOnBits(30) = CLng(2147483647)
    
    m_l2Power(0) = CLng(1)
    m_l2Power(1) = CLng(2)
    m_l2Power(2) = CLng(4)
    m_l2Power(3) = CLng(8)
    m_l2Power(4) = CLng(16)
    m_l2Power(5) = CLng(32)
    m_l2Power(6) = CLng(64)
    m_l2Power(7) = CLng(128)
    m_l2Power(8) = CLng(256)
    m_l2Power(9) = CLng(512)
    m_l2Power(10) = CLng(1024)
    m_l2Power(11) = CLng(2048)
    m_l2Power(12) = CLng(4096)
    m_l2Power(13) = CLng(8192)
    m_l2Power(14) = CLng(16384)
    m_l2Power(15) = CLng(32768)
    m_l2Power(16) = CLng(65536)
    m_l2Power(17) = CLng(131072)
    m_l2Power(18) = CLng(262144)
    m_l2Power(19) = CLng(524288)
    m_l2Power(20) = CLng(1048576)
    m_l2Power(21) = CLng(2097152)
    m_l2Power(22) = CLng(4194304)
    m_l2Power(23) = CLng(8388608)
    m_l2Power(24) = CLng(16777216)
    m_l2Power(25) = CLng(33554432)
    m_l2Power(26) = CLng(67108864)
    m_l2Power(27) = CLng(134217728)
    m_l2Power(28) = CLng(268435456)
    m_l2Power(29) = CLng(536870912)
    m_l2Power(30) = CLng(1073741824)


    Dim x
    Dim k
    Dim AA
    Dim BB
    Dim CC
    Dim DD
    Dim a
    Dim b
    Dim c
    Dim d
    
    Const S11 = 7
    Const S12 = 12
    Const S13 = 17
    Const S14 = 22
    Const S21 = 5
    Const S22 = 9
    Const S23 = 14
    Const S24 = 20
    Const S31 = 4
    Const S32 = 11
    Const S33 = 16
    Const S34 = 23
    Const S41 = 6
    Const S42 = 10
    Const S43 = 15
    Const S44 = 21

    x = ConvertToWordArray(sMessage)
    
    a = &H67452301
    b = &HEFCDAB89
    c = &H98BADCFE
    d = &H10325476

    For k = 0 To UBound(x) Step 16
        AA = a
        BB = b
        CC = c
        DD = d
    
        md5_FF a, b, c, d, x(k + 0), S11, &HD76AA478
        md5_FF d, a, b, c, x(k + 1), S12, &HE8C7B756
        md5_FF c, d, a, b, x(k + 2), S13, &H242070DB
        md5_FF b, c, d, a, x(k + 3), S14, &HC1BDCEEE
        md5_FF a, b, c, d, x(k + 4), S11, &HF57C0FAF
        md5_FF d, a, b, c, x(k + 5), S12, &H4787C62A
        md5_FF c, d, a, b, x(k + 6), S13, &HA8304613
        md5_FF b, c, d, a, x(k + 7), S14, &HFD469501
        md5_FF a, b, c, d, x(k + 8), S11, &H698098D8
        md5_FF d, a, b, c, x(k + 9), S12, &H8B44F7AF
        md5_FF c, d, a, b, x(k + 10), S13, &HFFFF5BB1
        md5_FF b, c, d, a, x(k + 11), S14, &H895CD7BE
        md5_FF a, b, c, d, x(k + 12), S11, &H6B901122
        md5_FF d, a, b, c, x(k + 13), S12, &HFD987193
        md5_FF c, d, a, b, x(k + 14), S13, &HA679438E
        md5_FF b, c, d, a, x(k + 15), S14, &H49B40821
    
        md5_GG a, b, c, d, x(k + 1), S21, &HF61E2562
        md5_GG d, a, b, c, x(k + 6), S22, &HC040B340
        md5_GG c, d, a, b, x(k + 11), S23, &H265E5A51
        md5_GG b, c, d, a, x(k + 0), S24, &HE9B6C7AA
        md5_GG a, b, c, d, x(k + 5), S21, &HD62F105D
        md5_GG d, a, b, c, x(k + 10), S22, &H2441453
        md5_GG c, d, a, b, x(k + 15), S23, &HD8A1E681
        md5_GG b, c, d, a, x(k + 4), S24, &HE7D3FBC8
        md5_GG a, b, c, d, x(k + 9), S21, &H21E1CDE6
        md5_GG d, a, b, c, x(k + 14), S22, &HC33707D6
        md5_GG c, d, a, b, x(k + 3), S23, &HF4D50D87
        md5_GG b, c, d, a, x(k + 8), S24, &H455A14ED
        md5_GG a, b, c, d, x(k + 13), S21, &HA9E3E905
        md5_GG d, a, b, c, x(k + 2), S22, &HFCEFA3F8
        md5_GG c, d, a, b, x(k + 7), S23, &H676F02D9
        md5_GG b, c, d, a, x(k + 12), S24, &H8D2A4C8A
            
        md5_HH a, b, c, d, x(k + 5), S31, &HFFFA3942
        md5_HH d, a, b, c, x(k + 8), S32, &H8771F681
        md5_HH c, d, a, b, x(k + 11), S33, &H6D9D6122
        md5_HH b, c, d, a, x(k + 14), S34, &HFDE5380C
        md5_HH a, b, c, d, x(k + 1), S31, &HA4BEEA44
        md5_HH d, a, b, c, x(k + 4), S32, &H4BDECFA9
        md5_HH c, d, a, b, x(k + 7), S33, &HF6BB4B60
        md5_HH b, c, d, a, x(k + 10), S34, &HBEBFBC70
        md5_HH a, b, c, d, x(k + 13), S31, &H289B7EC6
        md5_HH d, a, b, c, x(k + 0), S32, &HEAA127FA
        md5_HH c, d, a, b, x(k + 3), S33, &HD4EF3085
        md5_HH b, c, d, a, x(k + 6), S34, &H4881D05
        md5_HH a, b, c, d, x(k + 9), S31, &HD9D4D039
        md5_HH d, a, b, c, x(k + 12), S32, &HE6DB99E5
        md5_HH c, d, a, b, x(k + 15), S33, &H1FA27CF8
        md5_HH b, c, d, a, x(k + 2), S34, &HC4AC5665
    
        md5_II a, b, c, d, x(k + 0), S41, &HF4292244
        md5_II d, a, b, c, x(k + 7), S42, &H432AFF97
        md5_II c, d, a, b, x(k + 14), S43, &HAB9423A7
        md5_II b, c, d, a, x(k + 5), S44, &HFC93A039
        md5_II a, b, c, d, x(k + 12), S41, &H655B59C3
        md5_II d, a, b, c, x(k + 3), S42, &H8F0CCC92
        md5_II c, d, a, b, x(k + 10), S43, &HFFEFF47D
        md5_II b, c, d, a, x(k + 1), S44, &H85845DD1
        md5_II a, b, c, d, x(k + 8), S41, &H6FA87E4F
        md5_II d, a, b, c, x(k + 15), S42, &HFE2CE6E0
        md5_II c, d, a, b, x(k + 6), S43, &HA3014314
        md5_II b, c, d, a, x(k + 13), S44, &H4E0811A1
        md5_II a, b, c, d, x(k + 4), S41, &HF7537E82
        md5_II d, a, b, c, x(k + 11), S42, &HBD3AF235
        md5_II c, d, a, b, x(k + 2), S43, &H2AD7D2BB
        md5_II b, c, d, a, x(k + 9), S44, &HEB86D391
    
        a = AddUnsigned(a, AA)
        b = AddUnsigned(b, BB)
        c = AddUnsigned(c, CC)
        d = AddUnsigned(d, DD)
    Next
    
    Dim MD0, MD1, MD2, MD3, MD4
    
    MD0 = MD0 & Left(WordToHex(b), 2)
    MD0 = MD0 & Right(WordToHex(d), 2)
    MD1 = MD1 & Left(WordToHex(a), 1)
    MD1 = MD1 & Left(WordToHex(b), 1)
    MD1 = MD1 & Left(WordToHex(c), 1)
    MD1 = MD1 & Right(WordToHex(a), 1)
    MD1 = MD1 & Right(WordToHex(b), 1)
    MD1 = MD1 & Left(WordToHex(a), 1)
    
    MD2 = MD2 & Right(Asc(Mid(WordToHex(c), 5, 1)), 1)
    MD2 = MD2 & Left(Asc(Mid(WordToHex(d), 2, 1)), 1)
    MD2 = MD2 & Left(Asc(Mid(WordToHex(c), 6, 1)), 1)
    MD2 = MD2 & Right(Asc(Mid(WordToHex(d), 6, 1)), 1)
    MD2 = MD2 & Right(Mid(WordToHex(d), 6, 1), 1)
    MD2 = MD2 & Left(Mid(WordToHex(b), 6, 1), 1)
    
    MD3 = MD3 & Left(WordToHex(c), 6)
    
    MD4 = MD4 & Mid(WordToHex(a), 4, 3)
    MD4 = MD4 & Right(WordToHex(b), 3)
    
    MD5 = "bill" & MD0 & MD2 & MD1 & MD4 & MD3
    MD5 = LCase(MD5)
End Function
%>

加密之后是类似 bill5b876549e4b5cfcbac248cc405b1 这种密码。


Dim MD0, MD1, MD2, MD3, MD4

MD0 = MD0 & Left(WordToHex(b), 2)
MD0 = MD0 & Right(WordToHex(d), 2)

MD1 = MD1 & Left(WordToHex(a), 1)
MD1 = MD1 & Left(WordToHex(b), 1)
MD1 = MD1 & Left(WordToHex(c), 1)
MD1 = MD1 & Right(WordToHex(a), 1)
MD1 = MD1 & Right(WordToHex(b), 1)
MD1 = MD1 & Left(WordToHex(a), 1)

MD2 = MD2 & Right(Asc(Mid(WordToHex(c), 5, 1)), 1)
MD2 = MD2 & Left(Asc(Mid(WordToHex(d), 2, 1)), 1)
MD2 = MD2 & Left(Asc(Mid(WordToHex(c), 6, 1)), 1)
MD2 = MD2 & Right(Asc(Mid(WordToHex(d), 6, 1)), 1)
MD2 = MD2 & Right(Mid(WordToHex(d), 6, 1), 1)
MD2 = MD2 & Left(Mid(WordToHex(b), 6, 1), 1)

MD3 = MD3 & Left(WordToHex(c), 6)

MD4 = MD4 & Mid(WordToHex(a), 4, 3)
MD4 = MD4 & Right(WordToHex(b), 3)

MD5 = "bill" & MD0 & MD2 & MD1 & MD4 & MD3
MD5 = LCase(MD5)

除了最底下这段,上边的是标准的MD5加密模块。

一个自定义的拼接字符串的算法,等会,我看看能不能逆出来标准的MD5。

Dim MD0, MD1, MD2, MD3, MD4

MD0 = MD0 & Left(WordToHex(b), 2)
MD0 = MD0 & Right(WordToHex(d), 2)

MD1 = MD1 & Left(WordToHex(a), 1)
MD1 = MD1 & Left(WordToHex(b), 1)
MD1 = MD1 & Left(WordToHex(c), 1)
MD1 = MD1 & Right(WordToHex(a), 1)
MD1 = MD1 & Right(WordToHex(b), 1)
MD1 = MD1 & Left(WordToHex(a), 1)

MD2 = MD2 & Right(Asc(Mid(WordToHex(c), 5, 1)), 1)
MD2 = MD2 & Left(Asc(Mid(WordToHex(d), 2, 1)), 1)
MD2 = MD2 & Left(Asc(Mid(WordToHex(c), 6, 1)), 1)
MD2 = MD2 & Right(Asc(Mid(WordToHex(d), 6, 1)), 1)
MD2 = MD2 & Right(Mid(WordToHex(d), 6, 1), 1)
MD2 = MD2 & Left(Mid(WordToHex(b), 6, 1), 1)

MD3 = MD3 & Left(WordToHex(c), 6)

MD4 = MD4 & Mid(WordToHex(a), 4, 3)
MD4 = MD4 & Right(WordToHex(b), 3)

MD5 = "bill" & MD0 & MD2 & MD1 & MD4 & MD3
MD5 = LCase(MD5)

------------------------------------------------

Hash = bill5b876549e4b5cfcbac248cc405b1
Hash = bill 5b87 6549e4 b5cfcb ac248c c405b1

MD0 = 5b87
MD1 = b5cfcb
MD2 = 6549e4
MD3 = c405b1
MD4 = ac248c

a = b??ac2?f
b = 5b???48c
c = c405b1??
d = ??????87
'可以还原出abcd的值,由于太过于蛋疼,这里我只还原一部分,作为演示。
MD5 16 = bc
MD5 32 = abcd

明文密码:123456

标准密文:e10adc3949ba59abbe56e057f20f883e

变异密文:bill493e954689e4b9beadc9abbe56e0

还原变异:e??adc?949???9abbe56e0???*???83e

字符说明:? = 任意字母或数字,* = 一定范围内的字母或数字。

在密文变异的处理中,丢失了很多值,还有很多非固定值,如上所示。

理论上可以碰撞Hash,因为丢失的值可以为任意数。

也就是说这个加密后的结果,对应多个标准MD5值,也就是对应多个明文密码。

楼主可以给出一个加密后得值,可以找出多个可能的MD5值,目测大概最少有 (6+10)^12=281474976710656 个,还不算那些非固定的,当然,能以字符方式显示的明文密码要少很多,因为很多字符为不可显示字符,然后破解其中任意一条即可通过密码认证。

由于丢失了部分值,所以原加密字符串不得而知,但是可以肯定,原加密字符串就在这些碰撞出来的MD5之中。

总之,你只要拿到加密后得值,就可以还原出多条标准MD5密文,由于是可碰撞的,所以破解几率极高。

另外说一下,这他妈的就是一傻逼变异方式,由于可碰撞的密码数量极多!极容易通过碰撞算法解出密码,通过密码校验。。。。


已写出解密算法:

Private Function RndChr(R As String) As String
    Dim I As Long
    Randomize
    For I = 1 To Len(R)
        If Mid(R, I, 1) = " " Then
            If Int((2 * Rnd) + 1) = 1 Then
                R = Left(R, I - 1) & Chr(Int((57 - 48 + 1) * Rnd + 48)) & Mid(R, I + 1) '随机数字
            Else
                R = Left(R, I - 1) & Chr(Int((102 - 97 + 1) * Rnd + 97)) & Mid(R, I + 1) '随机字母
            End If
        End If
    Next
    RndChr = R
End Function

Private Function DeCode(s As String) As String
    Dim I As Long, II As Long, M(28) As String, x As String, a As String, b As String, c As String, d As String
    '---------------------------------------------------------------------------
    M(0) = " "
    For I = 1 To 28
        M(I) = Mid(s, I + 4, 1)
    Next
    '---------------------------------------------------------------------------
    a = M(16) & M(0) & M(0) & M(17) & M(18) & M(19) & M(0) & M(14)
    b = M(1) & M(2) & M(0) & M(0) & M(0) & M(20) & M(21) & M(22)
    c = M(23) & M(24) & M(25) & M(26) & M(27) & M(28) & M(0) & M(0)
    '---------------------------------------------------------------------------
    '针对【MD2 = MD2 & Left(Asc(Mid(WordToHex(d), 2, 1)), 1)】的碰撞循环
    If Val(M(6))  4, 50, 48)                                          '数字(48-57)
    Else
        I = IIf(Val(M(6)) > 6, 70, 65)                                          '大写字母(65-70)
    End If
    Do While ((I 

关于一种以“bill”开头的变异MD5加密方式的破解方法

每次生成100个随机碰撞出来的标准MD5值,然后拿去批量破解吧,随意破解一个即可。

同时给出编译好的程序下载地址:http://115.com/file/cl05p21e

用法:decode.exe billd6d79457c8cdd6ac9a681ad36014

留言评论(旧系统):

【匿名者】 @ 2012-05-06 01:09:11

大大,现在的解MD5的网站太坑爹了,简单的都收费,能否出个程序或者个建议?

本站回复:

不想掏钱,自己机器跑去,程序网上一堆。

文章来源于lcx.cc:关于一种以“bill”开头的变异MD5加密方式的破解方法

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