CWE-1023 缺失要素致使对比不完全

admin 2022年1月7日02:24:20CWE(弱点枚举)评论12 views1804字阅读6分0秒阅读模式

CWE-1023 缺失要素致使对比不完全

Incomplete Comparison with Missing Factors

结构: Simple

Abstraction: Base

状态: Incomplete

被利用可能性: unkown

基本描述

The software performs a comparison between entities that must consider multiple factors or characteristics of each entity, but the comparison does not include one or more of these factors. This can lead to resultant weaknesses, e.g. by operating on the wrong object.

相关缺陷

  • cwe_Nature: ChildOf cwe_CWE_ID: 697 cwe_View_ID: 1000 cwe_Ordinal: Primary

  • cwe_Nature: ChildOf cwe_CWE_ID: 697 cwe_View_ID: 699 cwe_Ordinal: Primary

适用平台

Language: {'cwe_Class': 'Language-Independent', 'cwe_Prevalence': 'Undetermined'}

常见的影响

范围 影响 注释
['Integrity', 'Access Control'] ['Alter Execution Logic', 'Bypass Protection Mechanism']

可能的缓解方案

Testing

策略:

Thoroughly test the comparison scheme before deploying code into production. Perform positive testing as well as negative testing.

示例代码

This example defines a fixed username and password. The AuthenticateUser() function is intended to accept a username and a password from an untrusted user, and check to ensure that it matches the username and password. If the username and password match, AuthenticateUser() is intended to indicate that authentication succeeded.

bad C

/ Ignore CWE-259 (hard-coded password) and CWE-309 (use of password system for authentication) for this example. /

char username = "admin";
char
pass = "password";

int AuthenticateUser(char inUser, char inPass) {

if (strncmp(username, inUser, strlen(inUser))) {

logEvent("Auth failure of username using strlen of inUser");
return(AUTH_FAIL);

}
if (! strncmp(pass, inPass, strlen(inPass))) {

logEvent("Auth success of password using strlen of inUser");
return(AUTH_SUCCESS);

}
else {

logEvent("Auth fail of password using sizeof");
return(AUTH_FAIL);

}

}

int main (int argc, char **argv) {

int authResult;
if (argc ExitError("Usage: Provide a username and password");

}
authResult = AuthenticateUser(argv[1], argv[2]);
if (authResult == AUTH_SUCCESS) {

DoAuthenticatedTask(argv[1]);

}
else {

ExitError("Authentication failed");

}

}文章来源于互联网:scap中文网

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  • 本文由 发表于 2022年1月7日02:24:20
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