首先讲一下正则的规则只需要管What How即可 其他无需考虑
.[abcd] [a-zA-Z] [^abcd]\d \s \t \w …
a* Greedy 贪婪a*? Lazy| 或^ $
使用数据如下：
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2 wangwei 200 false false 791 true 8 wangjing 200 false false 791 true 72 lihong 200 false false 791 true 94 wangxin 200 false false 791 true 107 liujuan 200 false false 791 true 119 zhangbo 200 false false 791 true 145 zhanghao 200 false false 791 true 169 zhangbin 200 false false 791 true 185 wangjing 200 false false 791 true 224 liuxin 200 false false 791 true 260 yanglin 200 false false 790 true 354 likai 200 false false 791 true 390 lixiang 200 false false 791 true 435 zhangbo 200 false false 791 true 436 wangxin 200 false false 791 true
推荐一个网站
https://regex101.com/
打开进行正则匹配
直接生成Python脚本
复制对应代码：
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# coding=utf8 # the above tag defines encoding for this document and is for Python 2.x compatibility import re regex = r"(\d+\s+)(\w+)(\s\d+\s\w+\s\w+\s\d+\s\w+)" test_str = ("2 wangwei 200 false false 791 true \n" "8 wangjing 200 false false 791 true \n" "72 lihong 200 false false 791 true \n" "94 wangxin 200 false false 791 true \n" "107 liujuan 200 false false 791 true \n" "119 zhangbo 200 false false 791 true \n" "145 zhanghao 200 false false 791 true \n" "169 zhangbin 200 false false 791 true \n" "185 wangjing 200 false false 791 true \n" "224 liuxin 200 false false 791 true \n" "260 yanglin 200 false false 790 true \n" "354 likai 200 false false 791 true \n" "390 lixiang 200 false false 791 true \n" "435 zhangbo 200 false false 791 true \n" "436 wangxin 200 false false 791 true ") matches = re.finditer(regex, test_str, re.MULTILINE) for matchNum, match in enumerate(matches, start=1): print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group())) for groupNum in range(0, len(match.groups())): groupNum = groupNum + 1 print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = match.start(groupNum), end = match.end(groupNum), group = match.group(groupNum))) # Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
修改为：
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# coding=utf8 # the above tag defines encoding for this document and is for Python 2.x compatibility import re regex = r"(\d+\s+)(\w+)(\s\d+\s\w+\s\w+\s\d+\s\w+)" test_str = ("2 wangwei 200 false false 791 true \n" "8 wangjing 200 false false 791 true \n" "72 lihong 200 false false 791 true \n" "94 wangxin 200 false false 791 true \n" "107 liujuan 200 false false 791 true \n" "119 zhangbo 200 false false 791 true \n" "145 zhanghao 200 false false 791 true \n" "169 zhangbin 200 false false 791 true \n" "185 wangjing 200 false false 791 true \n" "224 liuxin 200 false false 791 true \n" "260 yanglin 200 false false 790 true \n" "354 likai 200 false false 791 true \n" "390 lixiang 200 false false 791 true \n" "435 zhangbo 200 false false 791 true \n" "436 wangxin 200 false false 791 true ") matches = re.finditer(regex, test_str, re.MULTILINE) for i in matches: print(i.group(2))
使用vim进行正则匹配
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:s/abc/def/g 用def替换abc，g为global全局的意思 %s/200.*//g
参考链接：
https://regex101.com/
https://www.runoob.com/python/python-reg-expressions.html
https://www.cnblogs.com/penseur/archive/2011/02/25/1964522.html
https://gist.github.com/JavaCS3/e36e494e78a02049950bfa7c7ebeb929
FROM :ol4three.com | Author:ol4three
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