【Java】LeetCode题答-203移除链表元素

admin 2022年1月10日03:31:00评论13 views字数 1424阅读4分44秒阅读模式

LeetCood题目

image-20210626190731545

题答1(完整代码)

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/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
public ListNode removeElements(ListNode head, int val) {

while(head != null && head.val == val){
ListNode delNode = head;
head = head.next;
delNode.next = null;
}

if(head == null)
return head;

ListNode prev = head;
while(prev.next != null)
{
if(prev.next.val == val) {
ListNode delNode = prev.next;
prev.next = delNode.next;
delNode.next = null;
}
else
prev = prev.next;
}
return head;
}
}

题答2(利用虚拟头)

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/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution2 {
public ListNode removeElements(ListNode head, int val) {

ListNode dummyHead = new ListNode(-1);
dummyHead.next = head;


if(head == null)
return head;

ListNode prev = dummyHead;
while(prev.next != null)
{
if(prev.next.val == val) {
ListNode delNode = prev.next;
prev.next = delNode.next;
delNode.next = null;
}
else
prev = prev.next;
}
return dummyHead.next;
}

题解3(利用链表递归)和原理图

image-20210627024604937

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class Solution3 {
public ListNode removeElements(ListNode head, int val) {

if(head == null) //最小规模情况结束条件
return head;

head.next = removeElements(head.next, val);
return head.val == val ? head.next : head;

}

本地测试截图

image-20210626190930982

FROM:gylq.gitee Author:孤桜懶契

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  • 本文由 发表于 2022年1月10日03:31:00
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